Puzzle: You have two container - one can contain exactly 3 litres of water and the other can contain exactly 5 litres of water. How many minimum steps will you take to get exactly 4 litres of water without using any other container? You can assume the availability of sufficient quantity of water.
Solution: Find below the steps:-
- Step #1: fill the 5 litres container (3L - 0, 5L - 5)
- Step #2: fill the 3 litres container with the filled 5 litres container (3L - 3, 5L - 2)
- Step #3: empty the just filled 3 litres container (3L -0, 5L - 2)
- Step #4: transfer the 2 litres of water left in 5 litres container into 3 litres container (3L - 2, 5L - 0)
- Step #5: fill the 5 litres container (3L - 2, 5L - 5)
- Step #6: fill the 3 litres container (having 2L currently) using just filled 5 litres container (3L - 3, 5L - 4)
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5 comments:
this is really good
very good.. thanks alot...
or u can follow the following procedure...
i) Assuming both the containers empty, fill the 3 litre container and pour the water in 5 litre container.
so 3L-0, 5L-3
ii) Again fill the 3 litre container and pour the water in 5litre container until it gets full. As 5 litre container contains already 3 litre water, it will have more 2 litre water now (in all 5) and 3 litre container will have 1 litre left in it.
so 3L-1, 5L-5
iii) Throw the water in 5L container and pour all the water from 3litre container to 5L container.
So 3L-0, 5L-1.
iv) now fill the 3 litre container full and pour the water in 5litre container which will give us 4 litres of water.
A more involved version of the problem and the solution can be found here on CSE Blog
A more involved version of the problem and the solution can be found here on CSE Blog
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